3.412 \(\int \frac {(a+b x^2)^2 (c+d x^2)^3}{x^{3/2}} \, dx\)

Optimal. Leaf size=137 \[ \frac {2}{11} d x^{11/2} \left (a^2 d^2+6 a b c d+3 b^2 c^2\right )+\frac {2}{7} c x^{7/2} \left (3 a^2 d^2+6 a b c d+b^2 c^2\right )-\frac {2 a^2 c^3}{\sqrt {x}}+\frac {2}{3} a c^2 x^{3/2} (3 a d+2 b c)+\frac {2}{15} b d^2 x^{15/2} (2 a d+3 b c)+\frac {2}{19} b^2 d^3 x^{19/2} \]

[Out]

2/3*a*c^2*(3*a*d+2*b*c)*x^(3/2)+2/7*c*(3*a^2*d^2+6*a*b*c*d+b^2*c^2)*x^(7/2)+2/11*d*(a^2*d^2+6*a*b*c*d+3*b^2*c^
2)*x^(11/2)+2/15*b*d^2*(2*a*d+3*b*c)*x^(15/2)+2/19*b^2*d^3*x^(19/2)-2*a^2*c^3/x^(1/2)

________________________________________________________________________________________

Rubi [A]  time = 0.06, antiderivative size = 137, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.042, Rules used = {448} \[ \frac {2}{11} d x^{11/2} \left (a^2 d^2+6 a b c d+3 b^2 c^2\right )+\frac {2}{7} c x^{7/2} \left (3 a^2 d^2+6 a b c d+b^2 c^2\right )-\frac {2 a^2 c^3}{\sqrt {x}}+\frac {2}{3} a c^2 x^{3/2} (3 a d+2 b c)+\frac {2}{15} b d^2 x^{15/2} (2 a d+3 b c)+\frac {2}{19} b^2 d^3 x^{19/2} \]

Antiderivative was successfully verified.

[In]

Int[((a + b*x^2)^2*(c + d*x^2)^3)/x^(3/2),x]

[Out]

(-2*a^2*c^3)/Sqrt[x] + (2*a*c^2*(2*b*c + 3*a*d)*x^(3/2))/3 + (2*c*(b^2*c^2 + 6*a*b*c*d + 3*a^2*d^2)*x^(7/2))/7
+ (2*d*(3*b^2*c^2 + 6*a*b*c*d + a^2*d^2)*x^(11/2))/11 + (2*b*d^2*(3*b*c + 2*a*d)*x^(15/2))/15 + (2*b^2*d^3*x^
(19/2))/19

Rule 448

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Int[ExpandI
ntegrand[(e*x)^m*(a + b*x^n)^p*(c + d*x^n)^q, x], x] /; FreeQ[{a, b, c, d, e, m, n}, x] && NeQ[b*c - a*d, 0] &
& IGtQ[p, 0] && IGtQ[q, 0]

Rubi steps

\begin {align*} \int \frac {\left (a+b x^2\right )^2 \left (c+d x^2\right )^3}{x^{3/2}} \, dx &=\int \left (\frac {a^2 c^3}{x^{3/2}}+a c^2 (2 b c+3 a d) \sqrt {x}+c \left (b^2 c^2+6 a b c d+3 a^2 d^2\right ) x^{5/2}+d \left (3 b^2 c^2+6 a b c d+a^2 d^2\right ) x^{9/2}+b d^2 (3 b c+2 a d) x^{13/2}+b^2 d^3 x^{17/2}\right ) \, dx\\ &=-\frac {2 a^2 c^3}{\sqrt {x}}+\frac {2}{3} a c^2 (2 b c+3 a d) x^{3/2}+\frac {2}{7} c \left (b^2 c^2+6 a b c d+3 a^2 d^2\right ) x^{7/2}+\frac {2}{11} d \left (3 b^2 c^2+6 a b c d+a^2 d^2\right ) x^{11/2}+\frac {2}{15} b d^2 (3 b c+2 a d) x^{15/2}+\frac {2}{19} b^2 d^3 x^{19/2}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.05, size = 137, normalized size = 1.00 \[ \frac {2}{11} d x^{11/2} \left (a^2 d^2+6 a b c d+3 b^2 c^2\right )+\frac {2}{7} c x^{7/2} \left (3 a^2 d^2+6 a b c d+b^2 c^2\right )-\frac {2 a^2 c^3}{\sqrt {x}}+\frac {2}{3} a c^2 x^{3/2} (3 a d+2 b c)+\frac {2}{15} b d^2 x^{15/2} (2 a d+3 b c)+\frac {2}{19} b^2 d^3 x^{19/2} \]

Antiderivative was successfully verified.

[In]

Integrate[((a + b*x^2)^2*(c + d*x^2)^3)/x^(3/2),x]

[Out]

(-2*a^2*c^3)/Sqrt[x] + (2*a*c^2*(2*b*c + 3*a*d)*x^(3/2))/3 + (2*c*(b^2*c^2 + 6*a*b*c*d + 3*a^2*d^2)*x^(7/2))/7
+ (2*d*(3*b^2*c^2 + 6*a*b*c*d + a^2*d^2)*x^(11/2))/11 + (2*b*d^2*(3*b*c + 2*a*d)*x^(15/2))/15 + (2*b^2*d^3*x^
(19/2))/19

________________________________________________________________________________________

fricas [A]  time = 0.44, size = 129, normalized size = 0.94 \[ \frac {2 \, {\left (1155 \, b^{2} d^{3} x^{10} + 1463 \, {\left (3 \, b^{2} c d^{2} + 2 \, a b d^{3}\right )} x^{8} + 1995 \, {\left (3 \, b^{2} c^{2} d + 6 \, a b c d^{2} + a^{2} d^{3}\right )} x^{6} - 21945 \, a^{2} c^{3} + 3135 \, {\left (b^{2} c^{3} + 6 \, a b c^{2} d + 3 \, a^{2} c d^{2}\right )} x^{4} + 7315 \, {\left (2 \, a b c^{3} + 3 \, a^{2} c^{2} d\right )} x^{2}\right )}}{21945 \, \sqrt {x}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)^2*(d*x^2+c)^3/x^(3/2),x, algorithm="fricas")

[Out]

2/21945*(1155*b^2*d^3*x^10 + 1463*(3*b^2*c*d^2 + 2*a*b*d^3)*x^8 + 1995*(3*b^2*c^2*d + 6*a*b*c*d^2 + a^2*d^3)*x
^6 - 21945*a^2*c^3 + 3135*(b^2*c^3 + 6*a*b*c^2*d + 3*a^2*c*d^2)*x^4 + 7315*(2*a*b*c^3 + 3*a^2*c^2*d)*x^2)/sqrt
(x)

________________________________________________________________________________________

giac [A]  time = 0.31, size = 135, normalized size = 0.99 \[ \frac {2}{19} \, b^{2} d^{3} x^{\frac {19}{2}} + \frac {2}{5} \, b^{2} c d^{2} x^{\frac {15}{2}} + \frac {4}{15} \, a b d^{3} x^{\frac {15}{2}} + \frac {6}{11} \, b^{2} c^{2} d x^{\frac {11}{2}} + \frac {12}{11} \, a b c d^{2} x^{\frac {11}{2}} + \frac {2}{11} \, a^{2} d^{3} x^{\frac {11}{2}} + \frac {2}{7} \, b^{2} c^{3} x^{\frac {7}{2}} + \frac {12}{7} \, a b c^{2} d x^{\frac {7}{2}} + \frac {6}{7} \, a^{2} c d^{2} x^{\frac {7}{2}} + \frac {4}{3} \, a b c^{3} x^{\frac {3}{2}} + 2 \, a^{2} c^{2} d x^{\frac {3}{2}} - \frac {2 \, a^{2} c^{3}}{\sqrt {x}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)^2*(d*x^2+c)^3/x^(3/2),x, algorithm="giac")

[Out]

2/19*b^2*d^3*x^(19/2) + 2/5*b^2*c*d^2*x^(15/2) + 4/15*a*b*d^3*x^(15/2) + 6/11*b^2*c^2*d*x^(11/2) + 12/11*a*b*c
*d^2*x^(11/2) + 2/11*a^2*d^3*x^(11/2) + 2/7*b^2*c^3*x^(7/2) + 12/7*a*b*c^2*d*x^(7/2) + 6/7*a^2*c*d^2*x^(7/2) +
4/3*a*b*c^3*x^(3/2) + 2*a^2*c^2*d*x^(3/2) - 2*a^2*c^3/sqrt(x)

________________________________________________________________________________________

maple [A]  time = 0.01, size = 138, normalized size = 1.01 \[ -\frac {2 \left (-1155 b^{2} d^{3} x^{10}-2926 a b \,d^{3} x^{8}-4389 b^{2} c \,d^{2} x^{8}-1995 a^{2} d^{3} x^{6}-11970 a b c \,d^{2} x^{6}-5985 b^{2} c^{2} d \,x^{6}-9405 a^{2} c \,d^{2} x^{4}-18810 a b \,c^{2} d \,x^{4}-3135 b^{2} c^{3} x^{4}-21945 a^{2} c^{2} d \,x^{2}-14630 a b \,c^{3} x^{2}+21945 a^{2} c^{3}\right )}{21945 \sqrt {x}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^2+a)^2*(d*x^2+c)^3/x^(3/2),x)

[Out]

-2/21945*(-1155*b^2*d^3*x^10-2926*a*b*d^3*x^8-4389*b^2*c*d^2*x^8-1995*a^2*d^3*x^6-11970*a*b*c*d^2*x^6-5985*b^2
*c^2*d*x^6-9405*a^2*c*d^2*x^4-18810*a*b*c^2*d*x^4-3135*b^2*c^3*x^4-21945*a^2*c^2*d*x^2-14630*a*b*c^3*x^2+21945
*a^2*c^3)/x^(1/2)

________________________________________________________________________________________

maxima [A]  time = 1.11, size = 127, normalized size = 0.93 \[ \frac {2}{19} \, b^{2} d^{3} x^{\frac {19}{2}} + \frac {2}{15} \, {\left (3 \, b^{2} c d^{2} + 2 \, a b d^{3}\right )} x^{\frac {15}{2}} + \frac {2}{11} \, {\left (3 \, b^{2} c^{2} d + 6 \, a b c d^{2} + a^{2} d^{3}\right )} x^{\frac {11}{2}} - \frac {2 \, a^{2} c^{3}}{\sqrt {x}} + \frac {2}{7} \, {\left (b^{2} c^{3} + 6 \, a b c^{2} d + 3 \, a^{2} c d^{2}\right )} x^{\frac {7}{2}} + \frac {2}{3} \, {\left (2 \, a b c^{3} + 3 \, a^{2} c^{2} d\right )} x^{\frac {3}{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)^2*(d*x^2+c)^3/x^(3/2),x, algorithm="maxima")

[Out]

2/19*b^2*d^3*x^(19/2) + 2/15*(3*b^2*c*d^2 + 2*a*b*d^3)*x^(15/2) + 2/11*(3*b^2*c^2*d + 6*a*b*c*d^2 + a^2*d^3)*x
^(11/2) - 2*a^2*c^3/sqrt(x) + 2/7*(b^2*c^3 + 6*a*b*c^2*d + 3*a^2*c*d^2)*x^(7/2) + 2/3*(2*a*b*c^3 + 3*a^2*c^2*d
)*x^(3/2)

________________________________________________________________________________________

mupad [B]  time = 0.04, size = 119, normalized size = 0.87 \[ x^{7/2}\,\left (\frac {6\,a^2\,c\,d^2}{7}+\frac {12\,a\,b\,c^2\,d}{7}+\frac {2\,b^2\,c^3}{7}\right )+x^{11/2}\,\left (\frac {2\,a^2\,d^3}{11}+\frac {12\,a\,b\,c\,d^2}{11}+\frac {6\,b^2\,c^2\,d}{11}\right )-\frac {2\,a^2\,c^3}{\sqrt {x}}+\frac {2\,b^2\,d^3\,x^{19/2}}{19}+\frac {2\,a\,c^2\,x^{3/2}\,\left (3\,a\,d+2\,b\,c\right )}{3}+\frac {2\,b\,d^2\,x^{15/2}\,\left (2\,a\,d+3\,b\,c\right )}{15} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a + b*x^2)^2*(c + d*x^2)^3)/x^(3/2),x)

[Out]

x^(7/2)*((2*b^2*c^3)/7 + (6*a^2*c*d^2)/7 + (12*a*b*c^2*d)/7) + x^(11/2)*((2*a^2*d^3)/11 + (6*b^2*c^2*d)/11 + (
12*a*b*c*d^2)/11) - (2*a^2*c^3)/x^(1/2) + (2*b^2*d^3*x^(19/2))/19 + (2*a*c^2*x^(3/2)*(3*a*d + 2*b*c))/3 + (2*b
*d^2*x^(15/2)*(2*a*d + 3*b*c))/15

________________________________________________________________________________________

sympy [A]  time = 10.56, size = 189, normalized size = 1.38 \[ - \frac {2 a^{2} c^{3}}{\sqrt {x}} + 2 a^{2} c^{2} d x^{\frac {3}{2}} + \frac {6 a^{2} c d^{2} x^{\frac {7}{2}}}{7} + \frac {2 a^{2} d^{3} x^{\frac {11}{2}}}{11} + \frac {4 a b c^{3} x^{\frac {3}{2}}}{3} + \frac {12 a b c^{2} d x^{\frac {7}{2}}}{7} + \frac {12 a b c d^{2} x^{\frac {11}{2}}}{11} + \frac {4 a b d^{3} x^{\frac {15}{2}}}{15} + \frac {2 b^{2} c^{3} x^{\frac {7}{2}}}{7} + \frac {6 b^{2} c^{2} d x^{\frac {11}{2}}}{11} + \frac {2 b^{2} c d^{2} x^{\frac {15}{2}}}{5} + \frac {2 b^{2} d^{3} x^{\frac {19}{2}}}{19} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**2+a)**2*(d*x**2+c)**3/x**(3/2),x)

[Out]

-2*a**2*c**3/sqrt(x) + 2*a**2*c**2*d*x**(3/2) + 6*a**2*c*d**2*x**(7/2)/7 + 2*a**2*d**3*x**(11/2)/11 + 4*a*b*c*
*3*x**(3/2)/3 + 12*a*b*c**2*d*x**(7/2)/7 + 12*a*b*c*d**2*x**(11/2)/11 + 4*a*b*d**3*x**(15/2)/15 + 2*b**2*c**3*
x**(7/2)/7 + 6*b**2*c**2*d*x**(11/2)/11 + 2*b**2*c*d**2*x**(15/2)/5 + 2*b**2*d**3*x**(19/2)/19

________________________________________________________________________________________